the heat of vaporization of cometium is 8kj/mole. what is the heat of vaporization per gram based on the…

Explanation:

Step1: Recall the conversion formula

We know that to convert heat - of - vaporization from kJ/mole to kJ/g, we use the formula $\text{Heat of Vaporization per gram}=\frac{\text{Heat of Vaporization per mole}}{\text{Atomic mass}}$.

Step2: Substitute the given values

Given that the heat of vaporization per mole is $8\text{ kJ/mole}$ and the atomic mass is $20\text{ g/mole}$. So, $\text{Heat of Vaporization per gram}=\frac{8\text{ kJ/mole}}{20\text{ g/mole}}$.

Step3: Calculate the result

$\frac{8}{20}=0.4\text{ kJ/g}$.

Answer:

$0.4\text{ kJ/g}$