both hydrogen sulfide (h₂s) and ammonia (nh₃) have strong, unpleasant odors. which gas has the higher…

Explanation:

Step1: Recall Graham's law of effusion

According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to the square - root of its molar mass ($r\propto\frac{1}{\sqrt{M}}$), where $r$ is the rate of effusion and $M$ is the molar mass of the gas. The gas with the lower molar mass will have a higher effusion rate.

Step2: Calculate the molar mass of $H_2S$

The molar mass of $H_2S$: The molar mass of $H$ is approximately $1\ g/mol$ and the molar mass of $S$ is approximately $32\ g/mol$. So, $M_{H_2S}=2\times1 + 32=34\ g/mol$.

Step3: Calculate the molar mass of $NH_3$

The molar mass of $NH_3$: The molar mass of $N$ is approximately $14\ g/mol$ and the molar mass of $H$ is approximately $1\ g/mol$. So, $M_{NH_3}=14 + 3\times1=17\ g/mol$.

Step4: Compare the molar masses

Since $M_{NH_3}(17\ g/mol)<M_{H_2S}(34\ g/mol)$, according to Graham's law of effusion, $NH_3$ has a higher effusion rate.

Answer:

$NH_3$