for an ideal gas, 1 mole = ? l at stp.
for an ideal gas, 1 mole = ? l at stp.
Answer
Explanation:
Step1: Recall molar - volume at STP
At standard temperature and pressure (STP), which is defined as 0 °C (273.15 K) and 1 atm (101325 Pa), the molar volume of an ideal gas is a well - known constant. The molar volume $V_m$ of an ideal gas at STP is given by the formula $V_m=\frac{V}{n}$, where $V$ is the volume and $n$ is the number of moles. For an ideal gas at STP, $V_m = 22.4$ L/mol. When $n = 1$ mole, using the formula $V=n\times V_m$, we substitute $n = 1$ mol and $V_m=22.4$ L/mol.
Step2: Calculate the volume
$V=1\ mol\times22.4\ L/mol = 22.4$ L
Answer:
22.4