identify the acid - conjugate base pair in this balanced equation: h2so4 + 2naoh → 2h2o + na2so4 o h2so4/h2o…

identify the acid - conjugate base pair in this balanced equation: h2so4 + 2naoh → 2h2o + na2so4 o h2so4/h2o o h2so4/na2so4 o naoh/h2o o naoh/na2so4

identify the acid - conjugate base pair in this balanced equation: h2so4 + 2naoh → 2h2o + na2so4 o h2so4/h2o o h2so4/na2so4 o naoh/h2o o naoh/na2so4

Answer

Explanation:

Step1: Define acid - conjugate base pair

An acid donates a proton ($H^+$) to form its conjugate base. In the reaction $H_2SO_4 + 2NaOH\rightarrow2H_2O+Na_2SO_4$, $H_2SO_4$ is an acid.

Step2: Determine the conjugate base of $H_2SO_4$

When $H_2SO_4$ donates a proton, it forms $SO_4^{2 - }$. In the product $Na_2SO_4$, the anion is $SO_4^{2 - }$. So the acid - conjugate base pair is $H_2SO_4/Na_2SO_4$.

Answer:

$H_2SO_4/Na_2SO_4$