identify the correct lewis structure for if4+. select the single best answer.
identify the correct lewis structure for if4+. select the single best answer.
Answer
Explanation:
Step1: Determine valence - electrons
Iodine (I) has 7 valence electrons and each fluorine (F) has 7 valence electrons. For (IF_4^+), the total number of valence electrons is (7+(4\times7) - 1=34) (subtract 1 for the positive charge).
Step2: Arrange atoms and bond them
Iodine is the central atom. Each F is bonded to I with a single - bond. Each single - bond uses 2 electrons, so 8 electrons are used for the 4 I - F bonds.
Step3: Distribute remaining electrons
We have (34 - 8=26) electrons left. These are distributed as lone - pairs on the F atoms and I atom. Each F atom gets 3 lone - pairs (6 electrons per F), using (4\times6 = 24) electrons. The remaining (26-24 = 2) electrons are placed as a lone - pair on the I atom.
Step4: Check formal charges
The formal charge on I is (7-(2 + 4)=+1) (7 valence electrons initially, 2 non - bonding electrons and 4 electrons in bonds), and the formal charge on each F is (7-(6 + 1)=0).
The correct Lewis structure has I as the central atom, 4 single bonds to F atoms, 3 lone - pairs on each F atom, and 1 lone - pair on the I atom.
Answer:
The second structure from the top (where I has a lone - pair and each F has 3 lone - pairs and is singly bonded to I)