1. identify the number of valence electrons.\n2. put a check mark in the box to identify which elements will…
1. identify the number of valence electrons.\n2. put a check mark in the box to identify which elements will gain electrons and which will lose electrons.\nacids and bases\nbohr model # of valence elections will give away (lose) valence elections will add (gain) extra elections
Answer
Explanation:
Step1: Determine valence - electrons of H
Hydrogen (H) has atomic number 1. Its electron - configuration is 1s¹. So, it has 1 valence electron. It can lose this 1 electron to form H⁺ or gain 1 electron to have a full outer shell like helium.
Step2: Determine valence - electrons of O
Oxygen (O) has atomic number 8. Its electron - configuration is 1s²2s²2p⁴. The outer shell (n = 2) has 6 electrons, so it has 6 valence electrons. Oxygen is a non - metal and tends to gain 2 electrons to achieve a stable octet configuration.
Step3: General rule for metals and non - metals
Metals tend to lose electrons and non - metals tend to gain electrons.
Step4: Determine for other unspecified elements
Without knowing the specific elements, we follow the general rule based on their position in the periodic table. Non - metals (right side and top of the periodic table) gain electrons and metals (left side and bottom) lose electrons.
| Bohr Model | # of valence electrons | Will give away (lose) valence electrons | Will add (gain) extra electrons |
|---|---|---|---|
| H | 1 | Can lose (to form H⁺) | Can gain (to have 2 electrons like He) |
| O | 6 | No | Yes (needs 2 more for octet) |
Answer:
| Bohr Model | # of valence electrons | Will give away (lose) valence electrons | Will add (gain) extra electrons |
|---|---|---|---|
| H | 1 | √ | √ |
| O | 6 | √ |