identify the spectator ions in this reaction. check all that apply. 2h⁺ + co₃²⁻ + 2na⁺ + 2oh⁻ → 2na⁺ + co₃²⁻…

identify the spectator ions in this reaction. check all that apply. 2h⁺ + co₃²⁻ + 2na⁺ + 2oh⁻ → 2na⁺ + co₃²⁻ + 2h₂o h⁺ co₃²⁻ na⁺ oh⁻ 2h₂o done

identify the spectator ions in this reaction. check all that apply. 2h⁺ + co₃²⁻ + 2na⁺ + 2oh⁻ → 2na⁺ + co₃²⁻ + 2h₂o h⁺ co₃²⁻ na⁺ oh⁻ 2h₂o done

Answer

Answer:

B. $\text{CO}_3^{2 - }$, C. $\text{Na}^+$

Explanation:

Step1: Define spectator ions

Spectator ions are ions that do not participate in the net - ionic reaction. They are present in the same form on both the reactant and product sides of a chemical equation.

Step2: Analyze the given reaction

In the reaction $2\text{H}^+ + \text{CO}_3^{2 - }+2\text{Na}^+ + 2\text{OH}^-\rightarrow2\text{Na}^+ + \text{CO}_3^{2 - }+2\text{H}_2\text{O}$, we can see that $\text{Na}^+$ and $\text{CO}_3^{2 - }$ appear unchanged on both sides.

Step3: Identify non - spectator ions

$\text{H}^+$ and $\text{OH}^-$ react to form $\text{H}_2\text{O}$, so they are not spectator ions. $\text{H}_2\text{O}$ is a product and not an ion at all.