the initial temperature of a bomb calorimeter is 28.50°c. when a chemist carries out a reaction in this…

the initial temperature of a bomb calorimeter is 28.50°c. when a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°c. if the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 j/(g°c), how much heat is absorbed by the reaction? use q = mc_pδt. 140 j 418 j 1,470 j 5,170 j

the initial temperature of a bomb calorimeter is 28.50°c. when a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°c. if the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 j/(g°c), how much heat is absorbed by the reaction? use q = mc_pδt. 140 j 418 j 1,470 j 5,170 j

Answer

Explanation:

Step1: Convert mass to grams

$m = 1.400\ kg=1.400\times1000\ g = 1400\ g$

Step2: Calculate temperature change

$\Delta T=T_{final}-T_{initial}=27.45^{\circ}C - 28.50^{\circ}C=- 1.05^{\circ}C$

Step3: Calculate heat absorbed

$q = mC_p\Delta T=1400\ g\times3.52\ J/(g^{\circ}C)\times(-1.05^{\circ}C)=- 5174.4\ J$. The negative sign indicates heat is absorbed by the reaction. Rounding to the nearest ten gives $5170\ J$.

Answer:

$5,170\ J$