all ionic compounds\n1. write the formula for each compound (don’t forget to “check the charges”)\n1)…

all ionic compounds\n1. write the formula for each compound (don’t forget to “check the charges”)\n1) calcium acetate\n2) potassium chloride\n3) ammonium carbonate\n4) sodium nitride\n5) titanium (iv) hypochlorite\n6) iron (iii) sulfide\n7) zinc dichromate\n8) platinum (iv) oxide\n9) aluminium hydroxide\n10) mercury (ii) nitrate\n11) strontium fluoride\n12) tin (iv) hydrogen oxalate\n13) calcium peroxide\n14) gold (i) sulfate\n15) lead (iv) thiocyanate\n16) nickel (iii) sulfide
Answer
Explanation:
Step1: Identify ions and their charges
Calcium ion ($Ca^{2 + }$) and acetate ion ($C_{2}H_{3}O_{2}^{-}$). To balance charges, we need 2 acetate ions for 1 calcium ion. $Ca(C_{2}H_{3}O_{2})_{2}$
Step2: Identify ions and their charges
Potassium ion ($K^{+}$) and chloride ion ($Cl^{-}$). They combine in a 1:1 ratio. $KCl$
Step3: Identify ions and their charges
Ammonium ion ($NH_{4}^{+}$) and carbonate ion ($CO_{3}^{2 - }$). We need 2 ammonium ions to balance the - 2 charge of carbonate. $(NH_{4}){2}CO{3}$
Step4: Identify ions and their charges
Sodium ion ($Na^{+}$) and nitride ion ($N^{3 - }$). We need 3 sodium ions to balance the - 3 charge of nitride. $Na_{3}N$
Step5: Identify ions and their charges
Titanium(IV) ion ($Ti^{4+}$) and hypochlorite ion ($ClO^{-}$). We need 4 hypochlorite ions to balance the + 4 charge of titanium(IV). $Ti(ClO)_{4}$
Step6: Identify ions and their charges
Iron(III) ion ($Fe^{3+}$) and sulfide ion ($S^{2 - }$). To balance charges, the ratio is 2:3. $Fe_{2}S_{3}$
Step7: Identify ions and their charges
Zinc ion ($Zn^{2+}$) and dichromate ion ($Cr_{2}O_{7}^{2 - }$). They combine in a 1:1 ratio. $ZnCr_{2}O_{7}$
Step8: Identify ions and their charges
Platinum(IV) ion ($Pt^{4+}$) and oxide ion ($O^{2 - }$). We need 2 oxide ions to balance the + 4 charge of platinum(IV). $PtO_{2}$
Step9: Identify ions and their charges
Aluminium ion ($Al^{3+}$) and hydroxide ion ($OH^{-}$). We need 3 hydroxide ions to balance the + 3 charge of aluminium. $Al(OH)_{3}$
Step10: Identify ions and their charges
Mercury(II) ion ($Hg^{2+}$) and nitrate ion ($NO_{3}^{-}$). We need 2 nitrate ions to balance the + 2 charge of mercury(II). $Hg(NO_{3})_{2}$
Step11: Identify ions and their charges
Strontium ion ($Sr^{2+}$) and fluoride ion ($F^{-}$). We need 2 fluoride ions to balance the + 2 charge of strontium. $SrF_{2}$
Step12: Identify ions and their charges
Tin(IV) ion ($Sn^{4+}$) and hydrogen oxalate ion ($HC_{2}O_{4}^{-}$). We need 4 hydrogen - oxalate ions to balance the + 4 charge of tin(IV). $Sn(HC_{2}O_{4})_{4}$
Step13: Identify ions and their charges
Calcium ion ($Ca^{2+}$) and peroxide ion ($O_{2}^{2 - }$). They combine in a 1:1 ratio. $CaO_{2}$
Step14: Identify ions and their charges
Gold(I) ion ($Au^{+}$) and sulfate ion ($SO_{4}^{2 - }$). We need 2 gold(I) ions to balance the - 2 charge of sulfate. $Au_{2}SO_{4}$
Step15: Identify ions and their charges
Lead(IV) ion ($Pb^{4+}$) and thiocyanate ion ($SCN^{-}$). We need 4 thiocyanate ions to balance the + 4 charge of lead(IV). $Pb(SCN)_{4}$
Step16: Identify ions and their charges
Nickel(III) ion ($Ni^{3+}$) and sulfide ion ($S^{2 - }$). To balance charges, the ratio is 2:3. $Ni_{2}S_{3}$
Answer:
- $Ca(C_{2}H_{3}O_{2})_{2}$
- $KCl$
- $(NH_{4}){2}CO{3}$
- $Na_{3}N$
- $Ti(ClO)_{4}$
- $Fe_{2}S_{3}$
- $ZnCr_{2}O_{7}$
- $PtO_{2}$
- $Al(OH)_{3}$
- $Hg(NO_{3})_{2}$
- $SrF_{2}$
- $Sn(HC_{2}O_{4})_{4}$
- $CaO_{2}$
- $Au_{2}SO_{4}$
- $Pb(SCN)_{4}$
- $Ni_{2}S_{3}$