ions formation worksheet\ncomplete the following table.\nelement ionic symbol cation anion\nli\no\nn\nna\ns\n…

ions formation worksheet\ncomplete the following table.\nelement ionic symbol cation anion\nli\no\nn\nna\ns\nca\nbr\nk\nmg\nbe\nh\ni\ncl\nf\np\nse

ions formation worksheet\ncomplete the following table.\nelement ionic symbol cation anion\nli\no\nn\nna\ns\nca\nbr\nk\nmg\nbe\nh\ni\ncl\nf\np\nse

Answer

Explanation:

Step1: Determine ion - formation rules

Metals tend to lose electrons to form cations and non - metals tend to gain electrons to form anions. The number of electrons lost or gained is based on achieving a stable electron configuration (usually a noble - gas configuration).

Step2: Analyze Li

Lithium (Li) is a metal in Group 1. It has 1 valence electron and loses 1 electron to form a cation. The ionic symbol is $Li^+$, cation is $Li^+$, and there is no common simple anion for Li.

Step3: Analyze O

Oxygen (O) is a non - metal in Group 16. It has 6 valence electrons and gains 2 electrons to form an anion. The ionic symbol is $O^{2 - }$, anion is $O^{2 - }$, and there is no common simple cation for O.

Step4: Analyze N

Nitrogen (N) is a non - metal in Group 15. It has 5 valence electrons and gains 3 electrons to form an anion. The ionic symbol is $N^{3 - }$, anion is $N^{3 - }$, and there is no common simple cation for N.

Step5: Analyze Na

Sodium (Na) is a metal in Group 1. It has 1 valence electron and loses 1 electron to form a cation. The ionic symbol is $Na^+$, cation is $Na^+$, and there is no common simple anion for Na.

Step6: Analyze S

Sulfur (S) is a non - metal in Group 16. It has 6 valence electrons and gains 2 electrons to form an anion. The ionic symbol is $S^{2 - }$, anion is $S^{2 - }$, and there is no common simple cation for S.

Step7: Analyze Ca

Calcium (Ca) is a metal in Group 2. It has 2 valence electrons and loses 2 electrons to form a cation. The ionic symbol is $Ca^{2+}$, cation is $Ca^{2+}$, and there is no common simple anion for Ca.

Step8: Analyze Br

Bromine (Br) is a non - metal in Group 17. It has 7 valence electrons and gains 1 electron to form an anion. The ionic symbol is $Br^-$, anion is $Br^-$, and there is no common simple cation for Br.

Step9: Analyze K

Potassium (K) is a metal in Group 1. It has 1 valence electron and loses 1 electron to form a cation. The ionic symbol is $K^+$, cation is $K^+$, and there is no common simple anion for K.

Step10: Analyze Mg

Magnesium (Mg) is a metal in Group 2. It has 2 valence electrons and loses 2 electrons to form a cation. The ionic symbol is $Mg^{2+}$, cation is $Mg^{2+}$, and there is no common simple anion for Mg.

Step11: Analyze Be

Beryllium (Be) is a metal in Group 2. It has 2 valence electrons and loses 2 electrons to form a cation. The ionic symbol is $Be^{2+}$, cation is $Be^{2+}$, and there is no common simple anion for Be.

Step12: Analyze H

Hydrogen (H) can act as a metal and lose 1 electron to form $H^+$ (cation) or act as a non - metal and gain 1 electron to form $H^-$ (anion). The ionic symbols are $H^+$ and $H^-$, cation is $H^+$, anion is $H^-$.

Step13: Analyze I

Iodine (I) is a non - metal in Group 17. It has 7 valence electrons and gains 1 electron to form an anion. The ionic symbol is $I^-$, anion is $I^-$, and there is no common simple cation for I.

Step14: Analyze Cl

Chlorine (Cl) is a non - metal in Group 17. It has 7 valence electrons and gains 1 electron to form an anion. The ionic symbol is $Cl^-$, anion is $Cl^-$, and there is no common simple cation for Cl.

Step15: Analyze F

Fluorine (F) is a non - metal in Group 17. It has 7 valence electrons and gains 1 electron to form an anion. The ionic symbol is $F^-$, anion is $F^-$, and there is no common simple cation for F.

Step16: Analyze P

Phosphorus (P) is a non - metal in Group 15. It has 5 valence electrons and gains 3 electrons to form an anion. The ionic symbol is $P^{3 - }$, anion is $P^{3 - }$, and there is no common simple cation for P.

Step17: Analyze Se

Selenium (Se) is a non - metal in Group 16. It has 6 valence electrons and gains 2 electrons to form an anion. The ionic symbol is $Se^{2 - }$, anion is $Se^{2 - }$, and there is no common simple cation for Se.

Answer:

Element Ionic Symbol Cation Anion
Li $Li^+$ $Li^+$
O $O^{2 - }$ $O^{2 - }$
N $N^{3 - }$ $N^{3 - }$
Na $Na^+$ $Na^+$
S $S^{2 - }$ $S^{2 - }$
Ca $Ca^{2+}$ $Ca^{2+}$
Br $Br^-$ $Br^-$
K $K^+$ $K^+$
Mg $Mg^{2+}$ $Mg^{2+}$
Be $Be^{2+}$ $Be^{2+}$
H $H^+$, $H^-$ $H^+$ $H^-$
I $I^-$ $I^-$
Cl $Cl^-$ $Cl^-$
F $F^-$ $F^-$
P $P^{3 - }$ $P^{3 - }$
Se $Se^{2 - }$ $Se^{2 - }$