lana balanced an equation so that the result was 2c₂h₃br + 5o₂ → 4co₂ + 2h₂o + 2hbr. which most likely…

lana balanced an equation so that the result was 2c₂h₃br + 5o₂ → 4co₂ + 2h₂o + 2hbr. which most likely represents the starting equation?\no 2c₄h₃br + 5o₂ → 4co₂ + 2h₂o + 2hbr\no c₂h₃br + 5o₂ → 4co₂ + h₂o + 2hbr\no c₄h₃br + o₂ → co₂ + h₂o + hbr\no c₂h₃br + o₂ → co₂ + h₂o + hbr

lana balanced an equation so that the result was 2c₂h₃br + 5o₂ → 4co₂ + 2h₂o + 2hbr. which most likely represents the starting equation?\no 2c₄h₃br + 5o₂ → 4co₂ + 2h₂o + 2hbr\no c₂h₃br + 5o₂ → 4co₂ + h₂o + 2hbr\no c₄h₃br + o₂ → co₂ + h₂o + hbr\no c₂h₃br + o₂ → co₂ + h₂o + hbr

Answer

Explanation:

Step1: Analyze balanced equation

The balanced equation is $2C_2H_3Br + 5O_2\rightarrow4CO_2 + 2H_2O+2HBr$. The un - balanced equation should have the same reactants and products in a non - balanced state.

Step2: Check reactants and products

The reactants are $C_2H_3Br$ and $O_2$, and the products are $CO_2$, $H_2O$ and $HBr$.

Step3: Identify un - balanced form

The un - balanced form will have the general form $C_2H_3Br + O_2\rightarrow CO_2 + H_2O + HBr$.

Answer:

D. $C_2H_3Br + O_2\rightarrow CO_2 + H_2O + HBr$