law of conservation of mass experiment\nmaterial(s) mass (g)\nmass of test tube 42.78\nmass of steel wool…

law of conservation of mass experiment\nmaterial(s) mass (g)\nmass of test tube 42.78\nmass of steel wool 0.70\nmass of steel wool & test tube (original) 43.48\nmass of steel wool & test tube (after burning) ?\nstudents conduct an experiment in which steel wool is burned in a closed test tube. the steel wool reacts with an amount of oxygen equal to 1.48% of the mass of the steel wool. what is the correct value for the missing mass in the table?\na 0.71 g\nb 42.78 g\nc 43.48 g\nd 44.20 g

law of conservation of mass experiment\nmaterial(s) mass (g)\nmass of test tube 42.78\nmass of steel wool 0.70\nmass of steel wool & test tube (original) 43.48\nmass of steel wool & test tube (after burning) ?\nstudents conduct an experiment in which steel wool is burned in a closed test tube. the steel wool reacts with an amount of oxygen equal to 1.48% of the mass of the steel wool. what is the correct value for the missing mass in the table?\na 0.71 g\nb 42.78 g\nc 43.48 g\nd 44.20 g

Answer

Explanation:

Step1: Calculate mass of oxygen reacted

The mass of steel wool is $0.70$ g. The mass of oxygen that reacts is $1.48%$ of the mass of steel wool. So, mass of oxygen $=0.70\times\frac{1.48}{100}=0.70\times0.0148 = 0.01036$ g.

Step2: Apply law of conservation of mass

In a closed - system (the closed test - tube), the total mass before the reaction is equal to the total mass after the reaction. The total mass before the reaction is the mass of steel wool and test - tube which is $43.48$ g. After the reaction, the steel wool reacts with oxygen, but the total mass of the closed - system remains the same.

Answer:

C. $43.48$ g