li + alcl3 → licl + al\ntotal # before (reactants) elements total # after (products)\nli\nal\ncl
li + alcl3 → licl + al\ntotal # before (reactants) elements total # after (products)\nli\nal\ncl
Answer
Explanation:
Step1: Balance chlorine atoms
To balance the chlorine atoms, since there are 3 chlorine atoms in $AlCl_3$ and 1 in $LiCl$, we need 3 moles of $LiCl$. So the equation becomes $Li+AlCl_3\rightarrow3LiCl + Al$.
Step2: Balance lithium atoms
Now, to balance the lithium atoms, we need 3 moles of $Li$ on the left - hand side. The balanced equation is $3Li+AlCl_3\rightarrow3LiCl + Al$.
Step3: Fill in the element counts
| Total # Before (reactants) | Elements | Total # After (Products) |
|---|---|---|
| 3 | Li | 3 |
| 1 | Al | 1 |
| 3 | Cl | 3 |
Answer:
3, 1, 3, 1