li + alcl3 → licl + al\ntotal # before (reactants) elements total # after (products)\nli\nal\ncl

Explanation:

Step1: Balance Cl atoms

There are 3 Cl atoms in $AlCl_3$. So we need 3 moles of $LiCl$ on the product - side to balance the Cl atoms. The equation becomes $Li+AlCl_3\rightarrow3LiCl + Al$.

Step2: Balance Li atoms

Now, to balance the Li atoms, since we have 3 Li atoms in 3 moles of $LiCl$, we need 3 moles of Li on the reactant - side. The balanced equation is $3Li+AlCl_3\rightarrow3LiCl + Al$.

Answer:

3, 1, 3, 1