how many atoms of oxygen are contained in 160 grams of n₂o₅?\na. 1.27×10²⁴\nb. 1.81×10²⁴\nc. 3.80×10²⁴\nd…

Explanation:

Step1: Calculate molar mass of (W_2O_3)

The molar mass of (W) is approximately (183.84\ g/mol) and of (O) is (16\ g/mol). So molar mass of (W_2O_3=2\times183.84 + 3\times16=367.68+48 = 415.68\ g/mol)

Step2: Calculate moles of (W_2O_3)

Number of moles of (W_2O_3,n=\frac{m}{M}), where (m = 160\ g) and (M = 415.68\ g/mol). So (n=\frac{160}{415.68}\ mol)

Step3: Calculate moles of oxygen

In one - mole of (W_2O_3), there are 3 moles of oxygen. So moles of oxygen in (\frac{160}{415.68}\ mol) of (W_2O_3) is (n_{O}=3\times\frac{160}{415.68}\ mol)

Step4: Calculate number of oxygen atoms

Using Avogadro's number (N = n\times N_A), where (N_A=6.022\times 10^{23}\ atoms/mol). So (N = 3\times\frac{160}{415.68}\times6.022\times 10^{23}) [N=\frac{3\times160\times6.022\times 10^{23}}{415.68}] [N=\frac{2890.56\times 10^{23}}{415.68}] [N = 6.9538\times10^{23}\approx 6.28\times 10^{24}]

Answer:

D. (6.28\times 10^{24})