how many chlorine atoms are on the products side of the reaction 2al + 6hcl → 2alcl₃ + 3h₂?\n2\n3\n6\n9

how many chlorine atoms are on the products side of the reaction 2al + 6hcl → 2alcl₃ + 3h₂?\n2\n3\n6\n9

how many chlorine atoms are on the products side of the reaction 2al + 6hcl → 2alcl₃ + 3h₂?\n2\n3\n6\n9

Answer

Explanation:

Step1: Identify product with chlorine

The product with chlorine is $2AlCl_3$.

Step2: Calculate number of chlorine atoms

In $AlCl_3$, there are 3 chlorine atoms per formula - unit. With a coefficient of 2 for $AlCl_3$, the number of chlorine atoms is $2\times3 = 6$.

Answer:

C. 6