how many grams of co would be required to gen...
how many grams of co would be required to generate 635 g co₂?\nfe₂o₃ + 3co → 2fe + 3co₂\nco : 28.01 g/mol\nco₂ : 44.01 g/mol\n? g co
Answer
# Explanation:
## Step1: Calculate the number of moles of \(CO_2\)
The formula for the number of moles \(n=\frac{m}{M}\), where \(m\) is the mass and \(M\) is the molar mass.
Given \(m(CO_2) = 635\space g\) and \(M(CO_2)=44.01\space g/mol\)
\(n(CO_2)=\frac{635\space g}{44.01\space g/mol}\approx14.43\space mol\)
## Step2: Use the stoichiometric ratio from the balanced equation
From the balanced equation \(Fe_2O_3 + 3CO\rightarrow2Fe+3CO_2\), the ratio of \(n(CO)\) to \(n(CO_2)\) is \(1:1\) (since the coefficients of \(CO\) and \(CO_2\) are both \(3\)). So \(n(CO)=n(CO_2) = 14.43\space mol\)
## Step3: Calculate the mass of \(CO\)
Using the formula \(m = n\times M\), with \(n(CO)=14.43\space mol\) and \(M(CO) = 28.01\space g/mol\)
\(m(CO)=14.43\space mol\times28.01\space g/mol\approx404\space g\)
# Answer:
\(404\space g\)