how many grams of kr are in a 7.24 l cylinder at 14.7 °c and 7.77 atm? mass: g

Explanation:

Step1: Convert temperature to Kelvin

$T=(14.7 + 273.15)\text{ K}=287.85\text{ K}$

Step2: Use the ideal - gas law $PV = nRT$ to find the number of moles $n$

The ideal - gas constant $R = 0.0821\frac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}$, $P = 7.77\text{ atm}$, $V = 7.24\text{ L}$, $T=287.85\text{ K}$. $n=\frac{PV}{RT}=\frac{7.77\text{ atm}\times7.24\text{ L}}{0.0821\frac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\times287.85\text{ K}}$ $n=\frac{7.77\times7.24}{0.0821\times287.85}\text{ mol}\approx2.30\text{ mol}$

Step3: Calculate the mass of Kr

The molar mass of Kr is $M = 83.80\text{ g/mol}$. $m=n\times M=2.30\text{ mol}\times83.80\text{ g/mol}\approx193\text{ g}$

Answer:

$193$