how many grams are in 4.5 moles of sodium fluoride, naf?
how many grams are in 4.5 moles of sodium fluoride, naf?
Answer
Explanation:
Step1: Find molar - mass of NaF
The molar mass of Na (sodium) is approximately 22.99 g/mol and the molar mass of F (fluorine) is approximately 18.998 g/mol. The molar mass of NaF, $M_{NaF}=22.99 + 18.998=41.988$ g/mol.
Step2: Calculate mass
We use the formula $m = n\times M$, where $n = 4.5$ moles (the number of moles of NaF) and $M = 41.988$ g/mol (molar mass of NaF). So, $m=4.5\times41.988 = 188.946$ g.
Answer:
188.946 g