9.) how many molecules of caco₃ are present in 10.8 mol of calcium carbonate, (caco₃)? (3 points)

Explanation:

Step1: Recall Avogadro's number

Avogadro's number $N_A = 6.022\times 10^{23}$ molecules/mol.

Step2: Calculate the number of molecules

We use the formula $N = n\times N_A$, where $n = 10.8$ mol. So $N=10.8\times6.022\times 10^{23}$. $N = 6.50376\times 10^{24}$ molecules.

Answer:

$6.50376\times 10^{24}$ molecules