how many moles are in 223.2 g iron (fe)?\na. 4 moles\nb. 55.8 moles\nc. 26 moles\nd. 223.2 moles

how many moles are in 223.2 g iron (fe)?\na. 4 moles\nb. 55.8 moles\nc. 26 moles\nd. 223.2 moles

how many moles are in 223.2 g iron (fe)?\na. 4 moles\nb. 55.8 moles\nc. 26 moles\nd. 223.2 moles

Answer

Explanation:

Step1: Recall molar - mass formula

The formula to calculate the number of moles $n$ is $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar mass. The molar mass of iron (Fe) is approximately $M = 55.8\ g/mol$.

Step2: Substitute values

We are given $m = 223.2\ g$ and $M=55.8\ g/mol$. Substitute these values into the formula: $n=\frac{223.2\ g}{55.8\ g/mol}$.

Step3: Calculate the number of moles

$n=\frac{223.2}{55.8}=4\ mol$.

Answer:

A. 4 moles