how many moles are in 98.3 grams of aluminum hydroxide, al(oh)3?
how many moles are in 98.3 grams of aluminum hydroxide, al(oh)3?
Answer
Explanation:
Step1: Calculate molar mass of Al(OH)₃
The molar mass of Al = 26.98 g/mol, O = 16.00 g/mol, H = 1.01 g/mol. $M_{Al(OH)_3}=26.98 + 3\times(16.00 + 1.01)=26.98+3\times17.01 = 26.98 + 51.03=78.01$ g/mol
Step2: Calculate number of moles
Use the formula $n=\frac{m}{M}$, where $m = 98.3$ g and $M = 78.01$ g/mol. $n=\frac{98.3}{78.01}\approx1.26$ mol
Answer:
1.26 mol