how many moles of ba(no3)2 are there in 0.25 l of a 2.00 m ba(no3)2 solution? use molarity = \\frac{moles of…

how many moles of ba(no3)2 are there in 0.25 l of a 2.00 m ba(no3)2 solution? use molarity = \\frac{moles of solute}{liters of solution}.\n0.13 mol\n0.50 mol\n2.25 mol\n8.0 mol

how many moles of ba(no3)2 are there in 0.25 l of a 2.00 m ba(no3)2 solution? use molarity = \\frac{moles of solute}{liters of solution}.\n0.13 mol\n0.50 mol\n2.25 mol\n8.0 mol

Answer

Explanation:

Step1: Identify the formula

The formula for molarity is $M=\frac{n}{V}$, where $M$ is molarity, $n$ is moles of solute, and $V$ is volume of solution in liters. We need to solve for $n$.

Step2: Rearrange the formula

Rearranging for $n$ gives $n = M\times V$.

Step3: Substitute values

We are given $M = 2.00\ M$ and $V=0.25\ L$. Substituting these values into the formula: $n=2.00\ mol/L\times0.25\ L$.

Step4: Calculate

$n = 0.50\ mol$.

Answer:

0.50 mol