how many moles of hydrogen gas will be produced at the same time as 138 g naoh?\n2na + 2h₂o → 2naoh + h₂\n…

how many moles of hydrogen gas will be produced at the same time as 138 g naoh?\n2na + 2h₂o → 2naoh + h₂\n? mol h₂

how many moles of hydrogen gas will be produced at the same time as 138 g naoh?\n2na + 2h₂o → 2naoh + h₂\n? mol h₂

Answer

Answer:

1.5

Explanation:

Step1: Calculate moles of NaOH

The molar - mass of NaOH is (M_{NaOH}=23 + 16+1=40\ g/mol). The number of moles of NaOH, (n_{NaOH}=\frac{m}{M}=\frac{138\ g}{40\ g/mol}=3.45\ mol).

Step2: Use mole - ratio

From the balanced chemical equation (2Na + 2H_2O\rightarrow2NaOH + H_2), the mole - ratio of (NaOH) to (H_2) is (n_{NaOH}:n_{H_2}=2:1). Let the number of moles of (H_2) be (n_{H_2}). Then (\frac{n_{NaOH}}{n_{H_2}}=\frac{2}{1}). Substitute (n_{NaOH} = 3.45\ mol) into the ratio: (n_{H_2}=\frac{n_{NaOH}}{2}=\frac{3.45\ mol}{2}=1.5\ mol) (rounded to one decimal place).