how many moles nano3 would be produced from the complete reaction of 253 g na2cro4?\npb(no3)2 + na2cro4 →…

Answer:

3.00 mol

Explanation:

Step1: Calculate molar mass of Na₂CrO₄

The molar mass of Na₂CrO₄: $M(Na_2CrO_4)=2\times22.99 + 51.996+4\times15.999 = 161.974\ g/mol$

Step2: Calculate moles of Na₂CrO₄

$n(Na_2CrO_4)=\frac{m(Na_2CrO_4)}{M(Na_2CrO_4)}=\frac{253\ g}{161.974\ g/mol}\approx1.56\ mol$

Step3: Use mole - ratio from balanced equation

From the balanced equation $Pb(NO_3)_2 + Na_2CrO_4\rightarrow PbCrO_4 + 2NaNO_3$, the mole - ratio of $Na_2CrO_4$ to $NaNO_3$ is 1:2. $n(NaNO_3)=2\times n(Na_2CrO_4)$ $n(NaNO_3)=2\times1.56\ mol = 3.00\ mol$