3.) how many moles are present in 10.0 grams of sodium hydroxide (naoh)? (1 point)\n4 moles\n2 moles\n0.25…

3.) how many moles are present in 10.0 grams of sodium hydroxide (naoh)? (1 point)\n4 moles\n2 moles\n0.25 moles\n0.5 moles\n4.) the molar mass of sodium is 22.99 g/mol and the molar mass of chlorine is 35.45 g/mol. what is the mass in grams of 1.50 moles of sodium chlorine (nacl)?\nyour answer should be rounded to three significant figures.\n(1 point)\n87.66 g\n0.0257 g\n87.7 g\n0.02567 g

3.) how many moles are present in 10.0 grams of sodium hydroxide (naoh)? (1 point)\n4 moles\n2 moles\n0.25 moles\n0.5 moles\n4.) the molar mass of sodium is 22.99 g/mol and the molar mass of chlorine is 35.45 g/mol. what is the mass in grams of 1.50 moles of sodium chlorine (nacl)?\nyour answer should be rounded to three significant figures.\n(1 point)\n87.66 g\n0.0257 g\n87.7 g\n0.02567 g

Answer

Explanation:

Step1: Calculate molar mass of NaOH

The molar mass of Na ($22.99$ g/mol), O ($16.00$ g/mol), H ($1.01$ g/mol). Molar mass of NaOH = $22.99+16.00 + 1.01=40.00$ g/mol.

Step2: Calculate moles of NaOH

Use the formula $n=\frac{m}{M}$, where $m = 10.0$ g and $M = 40.00$ g/mol. So $n=\frac{10.0}{40.00}=0.25$ mol.

Step3: Calculate molar mass of NaCl

Molar mass of NaCl = molar mass of Na + molar mass of Cl = $22.99+35.45 = 58.44$ g/mol.

Step4: Calculate mass of 1.50 moles of NaCl

Use the formula $m=n\times M$, where $n = 1.50$ mol and $M = 58.44$ g/mol. So $m=1.50\times58.44 = 87.66$ g, rounded to three - significant figures is $87.7$ g.

Answer:

  1. C. 0.25 moles
  2. C. 87.7 g