1 mark for review which of the following bonds is most polar? a f - f b o - f c o - i d o - cl

Explanation:

Step1: Recall electronegativity concept

The polarity of a bond depends on the electronegativity difference ($\Delta \chi$) between the two atoms. The greater the $\Delta \chi$, the more polar the bond. The electronegativity values from the Pauling scale are: $\chi_F = 4.0$, $\chi_O=3.5$, $\chi_{Cl}=3.0$, $\chi_I = 2.5$.

Step2: Calculate $\Delta \chi$ for A

For F - F, since both atoms are the same, $\Delta \chi=4.0 - 4.0=0$.

Step3: Calculate $\Delta \chi$ for B

For O - F, $\Delta \chi = 4.0 - 3.5=0.5$.

Step4: Calculate $\Delta \chi$ for C

For O - I, $\Delta \chi=3.5 - 2.5 = 1.0$.

Step5: Calculate $\Delta \chi$ for D

For O - Cl, $\Delta \chi=3.5 - 3.0 = 0.5$.

Answer:

C. O-I