what is the mass of 3.01 x 10^23 molecules of c6h12o6? (1 mol c6h12o6 = 180.18 g) (1 mol c6h12o6 = 6.02 x…

what is the mass of 3.01 x 10^23 molecules of c6h12o6? (1 mol c6h12o6 = 180.18 g) (1 mol c6h12o6 = 6.02 x 10^23 molecules) ? g c6h12o6
Answer
Explanation:
Step1: Calculate the number of moles
Use Avogadro's number. Given $1$ mol = $6.02\times 10^{23}$ molecules. Let $n$ be the number of moles. Then $n=\frac{3.01\times 10^{23}\text{ molecules}}{6.02\times 10^{23}\text{ molecules/mol}}$. $n = 0.5$ mol
Step2: Calculate the mass
Given that the molar - mass of $C_6H_{12}O_6$ is $180.18$ g/mol. Let $m$ be the mass. Then $m=n\times M$, where $M = 180.18$ g/mol and $n = 0.5$ mol. $m=0.5\text{ mol}\times180.18\text{ g/mol}=90.09$ g
Answer:
$90.09$ g