what is the mass of 2.40 x 10^24 molecules of c3h8? (1 mole c3h8 = 44.11 g) (1 mole c3h8 = 6.02 x 10^23…

Explanation:

Step1: Calculate the number of moles

We know that 1 mole of any substance contains $6.02\times 10^{23}$ molecules. Let $n$ be the number of moles of $C_3H_8$. Using the proportion $\frac{n}{2.40\times 10^{24}}=\frac{1}{6.02\times 10^{23}}$, so $n=\frac{2.40\times 10^{24}}{6.02\times 10^{23}}$. $n=\frac{2.40\times 10^{24}}{6.02\times 10^{23}}\approx 3.99$ moles

Step2: Calculate the mass

We are given that 1 mole of $C_3H_8$ has a mass of 44.11 g. Let $m$ be the mass of $C_3H_8$. Using the formula $m = n\times M$ (where $M$ is the molar - mass), so $m=3.99\times44.11$. $m = 3.99\times44.11\approx176$ g

Answer:

176 g