the mass of a hydrogen atom is about 1.7×10⁻²⁴ g. the mass of a lead atom is about 3.4×10⁻²² g. the mass of…

Explanation:

Step1: Set up the division

To find out how many times the mass of a lead - atom is greater than the mass of a hydrogen - atom, we divide the mass of the lead atom by the mass of the hydrogen atom. Let $m_{lead}=3.4\times 10^{-22}$ g and $m_{hydrogen}=1.7\times 10^{-24}$ g. The expression is $\frac{m_{lead}}{m_{hydrogen}}=\frac{3.4\times 10^{-22}}{1.7\times 10^{-24}}$.

Step2: Divide the coefficients and subtract the exponents

First, divide the coefficients: $\frac{3.4}{1.7} = 2$. Then, use the rule of exponents $\frac{a^m}{a^n}=a^{m - n}$, so $\frac{10^{-22}}{10^{-24}}=10^{-22-(-24)}=10^{-22 + 24}=10^{2}$.

Step3: Combine the results

Multiply the results of the coefficient division and the exponent operation: $2\times10^{2}$.

Answer:

$2\times 10^{2}$