missed this? watch we 2.16; read section 2.10. you can click on the review link to access the section in…

missed this? watch we 2.16; read section 2.10. you can click on the review link to access the section in your e - text. acetone (fingernail - polish remover) has a density of 0.7857 g/cm³. you may want to reference (page) section 2.10 while completing this problem. part a what is the mass in grams of 18.26 ml of acetone? express your answer to four significant figures and include the appropriate units. mass = value units submit request answer

missed this? watch we 2.16; read section 2.10. you can click on the review link to access the section in your e - text. acetone (fingernail - polish remover) has a density of 0.7857 g/cm³. you may want to reference (page) section 2.10 while completing this problem. part a what is the mass in grams of 18.26 ml of acetone? express your answer to four significant figures and include the appropriate units. mass = value units submit request answer

Answer

Explanation:

Step1: Recall density - mass - volume formula

The density formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass, and $V$ is volume. We can re - arrange it to solve for mass: $m = \rho\times V$.

Step2: Convert volume units

Since $1\ mL=1\ cm^{3}$, the volume $V = 18.26\ mL=18.26\ cm^{3}$.

Step3: Calculate the mass

Given $\rho = 0.7857\ g/cm^{3}$ and $V = 18.26\ cm^{3}$, then $m=\rho\times V=0.7857\ g/cm^{3}\times18.26\ cm^{3}=14.356882\ g$.

Step4: Round to four significant figures

Rounding $14.356882\ g$ to four significant figures gives $14.36\ g$.

Answer:

$14.36\ g$