the molar heat of fusion of gold is 12.550 kj mol⁻¹. at its melting point, how much mass of melted gold must…

the molar heat of fusion of gold is 12.550 kj mol⁻¹. at its melting point, how much mass of melted gold must solidify to release 235.0 kj of energy? use q = nδh. 18.73 g 222.5 g 2,949.3 g 3,688.3 g

the molar heat of fusion of gold is 12.550 kj mol⁻¹. at its melting point, how much mass of melted gold must solidify to release 235.0 kj of energy? use q = nδh. 18.73 g 222.5 g 2,949.3 g 3,688.3 g

Answer

Explanation:

Step1: Encontrar el número de moles

Dado que $q = n\Delta H$, re - arreglamos la fórmula para $n$. Tenemos $n=\frac{q}{\Delta H}$. Sustituyendo $q = 235.0\ kJ$ y $\Delta H=12.550\ kJ/mol$, entonces $n=\frac{235.0\ kJ}{12.550\ kJ/mol}=18.725\ mol$.

Step2: Convertir moles a masa

La masa molar del oro ($Au$) es $M = 196.97\ g/mol$. Usando la fórmula $m=n\times M$, sustituyendo $n = 18.725\ mol$ y $M = 196.97\ g/mol$, obtenemos $m=18.725\ mol\times196.97\ g/mol\approx3688.3\ g$.

Answer:

3,688.3 g