the molar mass of oxygen gas (o2) is 32.00 g/mol. the molar mass of carbon dioxide (co2) is 44.01 g/mol…

Explanation:

Step1: Calculate moles of O2

The formula to calculate moles $n=\frac{m}{M}$, where $m$ is mass and $M$ is molar - mass. Given $m_{O_2}=8.94\ g$ and $M_{O_2} = 32.00\ g/mol$. So, $n_{O_2}=\frac{8.94\ g}{32.00\ g/mol}=0.279375\ mol$.

Step2: Determine mole - ratio

From the balanced chemical equation (not shown in the problem but assuming a complete combustion reaction where the ratio of $O_2$ to $CO_2$ is 1:1 for simplicity, as in the combustion of a hydrocarbon in excess oxygen), the mole - ratio of $O_2$ to $CO_2$ is 1:1. So, $n_{CO_2}=n_{O_2}=0.279375\ mol$.

Step3: Calculate mass of CO2

Using the formula $m = n\times M$, with $n_{CO_2}=0.279375\ mol$ and $M_{CO_2}=44.01\ g/mol$. Then $m_{CO_2}=0.279375\ mol\times44.01\ g/mol = 12.29539375\ g\approx13.0\ g$.

Answer:

13.0 grams