for every 1 molecule of glucose (c6h12o6) and 6 molecules of oxygen gas (o2) that go into cellular…

for every 1 molecule of glucose (c6h12o6) and 6 molecules of oxygen gas (o2) that go into cellular respiration, the process produces 6 molecules of carbon dioxide gas (co2) and 6 molecules of water (h2o). complete the table. type of atom number of atoms in 6 molecules of carbon dioxide number of atoms in 6 molecules of water total number of atoms in products h 0 12 c 0 o 12
Answer
Explanation:
Step1: Calculate number of C atoms in 6 CO₂
Each CO₂ has 1 C atom, so 6 CO₂ have 6×1 = 6 C atoms.
Step2: Calculate number of O atoms in 6 H₂O
Each H₂O has 1 O atom, so 6 H₂O have 6×1 = 6 O atoms.
Step3: Calculate total H atoms
There are 12 H atoms from 6 H₂O, so total H atoms in products is 12.
Step4: Calculate total C atoms
There are 6 C atoms from 6 CO₂, so total C atoms in products is 6.
Step5: Calculate total O atoms
There are 12 O atoms from 6 CO₂ and 6 O atoms from 6 H₂O, so total O atoms is 12 + 6=18.
Answer:
| Type of atom | Number of atoms in 6 molecules of carbon dioxide | Number of atoms in 6 molecules of water | Total number of atoms in products |
|---|---|---|---|
| H | 0 | 12 | 12 |
| C | 6 | 0 | 6 |
| O | 12 | 6 | 18 |