each molecule below has one chiral carbon. determine the absolute configuration (r/s) for each.\n\na. r…

each molecule below has one chiral carbon. determine the absolute configuration (r/s) for each.\n\na. r r\nb. r s\nc. s r\nd. s s

each molecule below has one chiral carbon. determine the absolute configuration (r/s) for each.\n\na. r r\nb. r s\nc. s r\nd. s s

Answer

Explanation:

Step1: Determine priorities for molecule I

Assign priorities to groups attached to chiral - carbon based on atomic number. F (highest atomic number) > ethyl > methyl > H. When the lowest - priority group (H) is facing away, the direction of the remaining groups is clock - wise, so it is R.

Step2: Determine priorities for molecule II

For molecule II, OH (highest priority due to O) > ethyl > methyl > H. When the lowest - priority group (H) is facing away, the direction of the remaining groups is counter - clockwise, so it is S.

Answer:

B. R, S