how much of a 0.250 m sucrose solution must be used to prepare 400.0 ml of a 0.0310 m solution? 49.6 ml…

how much of a 0.250 m sucrose solution must be used to prepare 400.0 ml of a 0.0310 m solution? 49.6 ml complete which statement best explains how the solution should be made? add 49.6 ml of 0.250 m sucrose to 400.0 ml of water to get 400.0 ml of 0.0310 m sucrose. add 49.6 ml of 0.0310 m sucrose to 350.4 ml of water to get 400.0 ml of 0.250 m sucrose. add 49.6 ml of 0.250 m sucrose to 350.4 ml of water to get 400.0 ml of 0.0310 m sucrose. done

how much of a 0.250 m sucrose solution must be used to prepare 400.0 ml of a 0.0310 m solution? 49.6 ml complete which statement best explains how the solution should be made? add 49.6 ml of 0.250 m sucrose to 400.0 ml of water to get 400.0 ml of 0.0310 m sucrose. add 49.6 ml of 0.0310 m sucrose to 350.4 ml of water to get 400.0 ml of 0.250 m sucrose. add 49.6 ml of 0.250 m sucrose to 350.4 ml of water to get 400.0 ml of 0.0310 m sucrose. done

Answer

Explanation:

Step1: Use dilution formula

$M_1V_1 = M_2V_2$, where $M_1$ is initial - concentration, $V_1$ is initial - volume, $M_2$ is final - concentration, and $V_2$ is final - volume. We know $M_1 = 0.250\ M$, $M_2 = 0.0310\ M$, and $V_2=400.0\ mL$. We need to find $V_1$.

Step2: Rearrange the formula to solve for $V_1$

$V_1=\frac{M_2V_2}{M_1}$ Substitute the values: $V_1=\frac{0.0310\ M\times400.0\ mL}{0.250\ M}=49.6\ mL$ To make the solution, we need to add the concentrated solution to some volume of water to get the final volume. The volume of water to be added is $V_{water}=V_2 - V_1=400.0\ mL - 49.6\ mL = 350.4\ mL$. So we add 49.6 mL of 0.250 M sucrose to 350.4 mL of water to get 400.0 mL of 0.0310 M sucrose.

Answer:

Add 49.6 mL of 0.250 M sucrose to 350.4 mL of water to get 400.0 mL of 0.0310 M sucrose.