how much of a 0.250 m sucrose solution must be used to prepare 400.0 ml of a 0.0310 m solution? 49.6 ml…

how much of a 0.250 m sucrose solution must be used to prepare 400.0 ml of a 0.0310 m solution? 49.6 ml complete which statement best explains how the solution should be made? add 49.6 ml of 0.250 m sucrose to 400.0 ml of water to get 400.0 ml of 0.0310 m sucrose. add 49.6 ml of 0.0310 m sucrose to 350.4 ml of water to get 400.0 ml of 0.250 m sucrose. add 49.6 ml of 0.250 m sucrose to 350.4 ml of water to get 400.0 ml of 0.0310 m sucrose. complete what is the molarity of the solution that results when 25.0 ml of 0.513 m solution is diluted to 500.0 ml? m done

how much of a 0.250 m sucrose solution must be used to prepare 400.0 ml of a 0.0310 m solution? 49.6 ml complete which statement best explains how the solution should be made? add 49.6 ml of 0.250 m sucrose to 400.0 ml of water to get 400.0 ml of 0.0310 m sucrose. add 49.6 ml of 0.0310 m sucrose to 350.4 ml of water to get 400.0 ml of 0.250 m sucrose. add 49.6 ml of 0.250 m sucrose to 350.4 ml of water to get 400.0 ml of 0.0310 m sucrose. complete what is the molarity of the solution that results when 25.0 ml of 0.513 m solution is diluted to 500.0 ml? m done

Answer

Answer:

0.0257

Explanation:

Step1: Recall dilution formula

$M_1V_1 = M_2V_2$

Step2: Identify given values

$M_1 = 0.513\ M$, $V_1=25.0\ mL$, $V_2 = 500.0\ mL$

Step3: Solve for $M_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{0.513\ M\times25.0\ mL}{500.0\ mL}= 0.0257\ M$