5) how much water would i need to add to 500 ml of a 2.4 m kcl solution to make a 1.0 m solution?

Explanation:

Step1: Calculate moles of KCl initially

Use the formula $n = M\times V$. Given $M_1=2.4\ M$ and $V_1 = 500\ mL=0.5\ L$. So $n = 2.4\ mol/L\times0.5\ L = 1.2\ mol$.

Step2: Calculate the final volume of the diluted solution

Use the formula $V_2=\frac{n}{M_2}$. Since $n = 1.2\ mol$ and $M_2 = 1.0\ M$, then $V_2=\frac{1.2\ mol}{1.0\ mol/L}=1.2\ L = 1200\ mL$.

Step3: Calculate the volume of water to add

The volume of water to add $V_{water}=V_2 - V_1$. So $V_{water}=1200\ mL - 500\ mL = 700\ mL$.

Answer:

700 mL