multiple choice 1 point\na compound is compos...
multiple choice 1 point\na compound is composed of 58.8% c, 9.8% h, and 31.4% o, and the molar mass is 102 g/mol. what is the molecular formula for this compound\nc₂h₁₀o₃\nc₅h₅o₃\nch₃o₃\nc₅h₁₀o₂\nclear my selection\nprevious
Answer
# Answer:
D. \(C_5H_{10}O_2\)
# Explanation:
## Step1: Assume 100g of the compound
So, \(m(C)=58.8g\), \(m(H) = 9.8g\), \(m(O)=31.4g\)
## Step2: Calculate the number of moles of each element
- For \(C\): \(n(C)=\frac{m(C)}{M(C)}=\frac{58.8g}{12g/mol}=4.9mol\approx5mol\)
- For \(H\): \(n(H)=\frac{m(H)}{M(H)}=\frac{9.8g}{1g/mol}=9.8mol\approx10mol\)
- For \(O\): \(n(O)=\frac{m(O)}{M(O)}=\frac{31.4g}{16g/mol}=1.96mol\approx2mol\)
The empirical formula is \(C_5H_{10}O_2\)
## Step3: Calculate the molar mass of the empirical formula
\(M_{empirical}=(5\times12 + 10\times1+2\times16)g/mol=(60 + 10+32)g/mol = 102g/mol\)
Since the molar mass of the compound (\(102g/mol\)) is equal to the molar mass of the empirical formula (\(C_5H_{10}O_2\)), the molecular formula is the same as the empirical formula.