name: \nchemical bonds - ionic vs. covalent\ndirections: using the table below define each of the given bond…

name: \nchemical bonds - ionic vs. covalent\ndirections: using the table below define each of the given bond types. then work to identify the types of bonds in the given compounds.\n| bond type | definition |\n|--|--|--|--|\n| ionic | |\n| covalent (polar and non - polar) | |\n| metallic | |\n| compound | element #1 (m or nm) | element #2 (m or nm) | bond type |\n|--|--|--|--|\n| nacl | m | nm | ionic |\n| h₂o | | | |\n| ch₄ | | | |\n| caf₂ | | | |\n| nh₃ | | | |\n| ccl₄ | | | |\n| kbr | | | |\n| br₂ | | | |\n| alloy of cu and zn (brass) | | | |

name: \nchemical bonds - ionic vs. covalent\ndirections: using the table below define each of the given bond types. then work to identify the types of bonds in the given compounds.\n| bond type | definition |\n|--|--|--|--|\n| ionic | |\n| covalent (polar and non - polar) | |\n| metallic | |\n| compound | element #1 (m or nm) | element #2 (m or nm) | bond type |\n|--|--|--|--|\n| nacl | m | nm | ionic |\n| h₂o | | | |\n| ch₄ | | | |\n| caf₂ | | | |\n| nh₃ | | | |\n| ccl₄ | | | |\n| kbr | | | |\n| br₂ | | | |\n| alloy of cu and zn (brass) | | | |

Answer

Explanation:

Step1: Recall bond - type rules

Ionic bonds form between a metal (M) and a non - metal (NM). Covalent bonds form between non - metals. Metallic bonds are in metals or metal alloys.

Step2: Analyze $H_2O$

Hydrogen ($H$) is a non - metal and oxygen ($O$) is a non - metal. So, the bond in $H_2O$ is covalent. Since oxygen is more electronegative than hydrogen, it is a polar covalent bond. Element #1 (H) is NM, Element #2 (O) is NM, Bond Type is Covalent (Polar).

Step3: Analyze $CH_4$

Carbon ($C$) and hydrogen ($H$) are non - metals. The bond in $CH_4$ is covalent. The electronegativity difference is small, so it is a non - polar covalent bond. Element #1 (C) is NM, Element #2 (H) is NM, Bond Type is Covalent (Non - Polar).

Step4: Analyze $CaF_2$

Calcium ($Ca$) is a metal and fluorine ($F$) is a non - metal. So, the bond in $CaF_2$ is ionic. Element #1 (Ca) is M, Element #2 (F) is NM, Bond Type is Ionic.

Step5: Analyze $NH_3$

Nitrogen ($N$) and hydrogen ($H$) are non - metals. Nitrogen is more electronegative than hydrogen, so the bond in $NH_3$ is a polar covalent bond. Element #1 (N) is NM, Element #2 (H) is NM, Bond Type is Covalent (Polar).

Step6: Analyze $CCl_4$

Carbon ($C$) and chlorine ($Cl$) are non - metals. The electronegativity difference leads to polar bonds, but due to the symmetrical structure, $CCl_4$ has non - polar covalent bonds overall. Element #1 (C) is NM, Element #2 (Cl) is NM, Bond Type is Covalent (Non - Polar).

Step7: Analyze $KBr$

Potassium ($K$) is a metal and bromine ($Br$) is a non - metal. So, the bond in $KBr$ is ionic. Element #1 (K) is M, Element #2 (Br) is NM, Bond Type is Ionic.

Step8: Analyze $Br_2$

Bromine ($Br$) is a non - metal. Two bromine atoms form a non - polar covalent bond. Element #1 (Br) is NM, Element #2 (Br) is NM, Bond Type is Covalent (Non - Polar).

Step9: Analyze Brass (Alloy of Cu and Zn)

Copper ($Cu$) and zinc ($Zn$) are metals. The bond in brass is metallic. Element #1 (Cu) is M, Element #2 (Zn) is M, Bond Type is Metallic.

Answer:

Compound Element #1 (M or NM) Element #2 (M or NM) Bond Type
$H_2O$ NM NM Covalent (Polar)
$CH_4$ NM NM Covalent (Non - Polar)
$CaF_2$ M NM Ionic
$NH_3$ NM NM Covalent (Polar)
$CCl_4$ NM NM Covalent (Non - Polar)
$KBr$ M NM Ionic
$Br_2$ NM NM Covalent (Non - Polar)
Alloy of Cu and Zn (Brass) M M Metallic