name: date: period: version b\npart 1\nunit quiz 2a - electronic structure\ncomplete the table below by…

name: date: period: version b\npart 1\nunit quiz 2a - electronic structure\ncomplete the table below by filling in the missing information. all elements in the table are neutral.\ngive the full electron configuration for elements with less than 18 electrons.\ngive the noble gas electron configuration for elements with more than 18 electrons.\n| element symbol | total number of electrons | electron configuration | number of valence electrons | lewis dot structure |\n| ---- | ---- | ---- | ---- | ---- |\n| al | | | | - |\n| | | 1s²2s²2p⁶3s²3p³ | | - |\n| | | | | •as• |\npart 2\nin the box to the right, construct the lewis dot structure of the neutral element with an electron - configuration of 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p².\n| lewis dot structure |\n| ---- |

name: date: period: version b\npart 1\nunit quiz 2a - electronic structure\ncomplete the table below by filling in the missing information. all elements in the table are neutral.\ngive the full electron configuration for elements with less than 18 electrons.\ngive the noble gas electron configuration for elements with more than 18 electrons.\n| element symbol | total number of electrons | electron configuration | number of valence electrons | lewis dot structure |\n| ---- | ---- | ---- | ---- | ---- |\n| al | | | | - |\n| | | 1s²2s²2p⁶3s²3p³ | | - |\n| | | | | •as• |\npart 2\nin the box to the right, construct the lewis dot structure of the neutral element with an electron - configuration of 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p².\n| lewis dot structure |\n| ---- |

Answer

Explanation:

Step1: Determine electrons for Al

Al (aluminum) has an atomic number of 13, so the total number of electrons is 13.

Step2: Write electron - configuration for Al

The full electron - configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$.

Step3: Find valence electrons for Al

The outermost shell electrons are valence electrons. For Al, in the 3s and 3p sub - shells, there are 2 + 1=3 valence electrons.

Step4: Analyze given electron - configuration $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$

The total number of electrons is 2 + 2+6 + 2+3 = 15. The element with 15 electrons is P (phosphorus). It has 5 valence electrons (3s²3p³).

Step5: Analyze Lewis dot structure of As

As (arsenic) has 5 valence electrons. The Lewis dot structure shows 5 dots around the symbol As.

Step6: Analyze given electron - configuration $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{2}$

The total number of electrons is 2+2 + 6+2+6+2+10+6+2+10+2 = 50. The element with 50 electrons is Sn (tin). It has 4 valence electrons (5s²5p²), and the Lewis dot structure has 4 dots around the Sn symbol.

ELEMENT SYMBOL TOTAL NUMBER OF ELECTRONS ELECTRON CONFIGURATION NUMBER OF VALENCE ELECTRONS LEWIS DOT STRUCTURE
Al 13 $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$ 3 $\cdot$Al$\cdot$
P 15 $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ 5 $\cdot$P$\cdot$<br>$\cdot$
As 33 - 5 $\cdot$As$\cdot$
Sn 50 $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{2}$ 4 $\cdot$Sn$\cdot$

Answer:

ELEMENT SYMBOL TOTAL NUMBER OF ELECTRONS ELECTRON CONFIGURATION NUMBER OF VALENCE ELECTRONS LEWIS DOT STRUCTURE
Al 13 $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$ 3 $\cdot$Al$\cdot$
P 15 $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ 5 $\cdot$P$\cdot$<br>$\cdot$
As 33 - 5 $\cdot$As$\cdot$
Sn 50 $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{2}$ 4 $\cdot$Sn$\cdot$