name the following binary (type iii) compounds\na. ccl₄\n b. no₂\n c. if₃\n d. co\n e. n₂o₄

Explanation:

Step1: Name compound a

For $CCl_4$, carbon is the first - named element and there is 1 carbon atom, and chlorine is the second - named element with 4 atoms. The prefix for 4 is "tetra -", so it is carbon tetrachloride.

Step2: Name compound b

For $NO_2$, nitrogen is the first - named element and oxygen is the second - named element. There is 1 nitrogen atom and 2 oxygen atoms. The prefix for 2 is "di -", so it is nitrogen dioxide.

Step3: Name compound c

For $IF_3$, iodine is the first - named element and fluorine is the second - named element. There is 1 iodine atom and 3 fluorine atoms. The prefix for 3 is "tri -", so it is iodine trifluoride.

Step4: Name compound d

For $CO$, carbon is the first - named element and oxygen is the second - named element. There is 1 carbon atom and 1 oxygen atom. The prefix for 1 in the second - named element is "mono -", so it is carbon monoxide.

Step5: Name compound e

For $N_2O_4$, nitrogen is the first - named element and oxygen is the second - named element. There are 2 nitrogen atoms (prefix "di -") and 4 oxygen atoms (prefix "tetra -"), so it is dinitrogen tetroxide.

Answer:

a. Carbon tetrachloride b. Nitrogen dioxide c. Iodine trifluoride d. Carbon monoxide e. Dinitrogen tetroxide