name: quiz chapter 1 chem 2300\n1. (2 pts) expand the following structural representations; show all the…

name: quiz chapter 1 chem 2300\n1. (2 pts) expand the following structural representations; show all the atoms and any unshared electron pairs.\n a.\n occurs in bay and verbena oil\n b.\n oh\n present in oil of cloves\n2. (2 pts) circle the compound in each of the following pairs that wont you expect to have the greater dipole moment μ? explain\n a. (ch₃)₂ch or (ch₃)₃ccl\n b. ch₃nh₂ or ch₃oh\n3. (1 pt) write a resonance structure of the following. use curved arrows to show how to transform the original lewis formula to the new one. be sure to specify formal charges, if any.\n h - c - o⁻\n o - h\n4. (3 pts) following the curved arrows, complete the equation to show the products formed. identify the acid, base, conjugate acid, and conjugate base.\n o:\n + h - sch₃\n5. (2 pt) write a lewis formula for each of the following: c₂h₃cl (vinyl chloride: starting material for the preparation of pvc plastics)
Answer
Explanation:
Step1: Problem 1a - Expand structure
Draw out all atoms and lone - pair electrons for the compound in bay and verbena oil. Each carbon atom forms 4 bonds, hydrogen forms 1 bond, and double - bonded carbons have the appropriate number of hydrogens to satisfy the octet rule.
Step1: Problem 1b - Expand structure
For the compound in oil of cloves, show all atoms and lone - pair electrons. The oxygen in the hydroxyl group has 2 lone pairs of electrons and the carbon atoms have the correct number of hydrogens to complete their octets.
Step2: Problem 2a - Dipole moment comparison
$(CH_3)_3CCl$ has a greater dipole moment than $(CH_3)_3CH$. Chlorine is more electronegative than hydrogen. In $(CH_3)_3CCl$, the C - Cl bond is polar, creating a significant dipole, while in $(CH_3)_3CH$, the C - H bonds are relatively non - polar.
Step2: Problem 2b - Dipole moment comparison
$CH_3OH$ has a greater dipole moment than $CH_3NH_2$. Oxygen is more electronegative than nitrogen. The O - H bond in $CH_3OH$ is more polar than the N - H bond in $CH_3NH_2$, resulting in a larger dipole moment for $CH_3OH$.
Step3: Problem 3 - Resonance structure
The resonance structure of the given molecule can be drawn by moving the lone pair of electrons on the negatively charged oxygen to form a double bond with the carbon, and moving the $\pi$ - bond electrons to the other oxygen. The formal charges are: the oxygen that gains a bond has a formal charge of 0, and the oxygen that loses the $\pi$ - bond has a formal charge of - 1.
Step4: Problem 4 - Acid - base reaction
The reaction is: $R - O^-+H - SCH_3\rightarrow R - OH+CH_3S^-$. The base is $R - O^-$, the acid is $H - SCH_3$, the conjugate acid is $R - OH$, and the conjugate base is $CH_3S^-$.
Step5: Problem 5 - Lewis formula
For $C_2H_3Cl$ (vinyl chloride), the Lewis formula has a double bond between the two carbon atoms. One carbon has two hydrogens and the other carbon has one hydrogen and one chlorine. Each atom has a complete octet (except hydrogen which has a duet).
Answer:
Answers for each problem are provided in the step - by - step explanations above for structure expansions, dipole moment comparisons, resonance structure drawing, acid - base identification, and Lewis formula writing.