naming and formula for polyatomic compounds\n73. calcium nitrite ca(no₂)₂\n74. baso₄\n75. silver…

Explanation:

Step1: Recall ion - charge rules

For naming and formula - writing of polyatomic compounds, we need to know the charges of cations and polyatomic anions. For example, calcium has a + 2 charge ($Ca^{2 + }$), and nitrite is $NO_{2}^{-}$. To balance the charges in calcium nitrite, we need 2 nitrite ions, so the formula is $Ca(NO_{2})_{2}$.

Step2: Identify polyatomic anions

For $BaSO_{4}$, $Ba^{2 + }$ is barium ion and $SO_{4}^{2 - }$ is sulfate ion, so the name is barium sulfate.

Step3: Apply for other compounds

Silver acetate: Silver has a + 1 charge ($Ag^{+}$) and acetate is $C_{2}H_{3}O_{2}^{-}$, so the formula is $AgC_{2}H_{3}O_{2}$. $SrSO_{3}$: $Sr^{2 + }$ is strontium ion and $SO_{3}^{2 - }$ is sulfite ion, so the name is strontium sulfite. Nickel(II) phosphate: Nickel(II) has a + 2 charge ($Ni^{2 + }$) and phosphate is $PO_{4}^{3 - }$. To balance the charges, the formula is $Ni_{3}(PO_{4}){2}$. $LiHCO{3}$: $Li^{+}$ is lithium ion and $HCO_{3}^{-}$ is bicarbonate ion, so the name is lithium bicarbonate. Ammonium phosphate: Ammonium is $NH_{4}^{+}$ and phosphate is $PO_{4}^{3 - }$, so the formula is $(NH_{4}){3}PO{4}$. Aluminum oxalate: Aluminum has a + 3 charge ($Al^{3 + }$) and oxalate is $C_{2}O_{4}^{2 - }$, so the formula is $Al_{2}(C_{2}O_{4}){3}$. Calcium hydroxide: Calcium is $Ca^{2 + }$ and hydroxide is $OH^{-}$, so the formula is $Ca(OH){2}$. $NH_{4}OH$: The name is ammonium hydroxide. Rubidium dichromate: Rubidium has a + 1 charge ($Rb^{+}$) and dichromate is $Cr_{2}O_{7}^{2 - }$, so the formula is $Rb_{2}Cr_{2}O_{7}$. $CuClO_{3}$: Copper(I) has a + 1 charge ($Cu^{+}$) and chlorate is $ClO_{3}^{-}$, so the name is copper(I) chlorate. $Ti(OH){4}$: Titanium(IV) has a + 4 charge ($Ti^{4 + }$) and hydroxide is $OH^{-}$, so the name is titanium(IV) hydroxide. Ammonium chloride: Ammonium is $NH{4}^{+}$ and chloride is $Cl^{-}$, so the formula is $NH_{4}Cl$. $Ca(ClO_{3}){2}$: Calcium is $Ca^{2 + }$ and chlorate is $ClO{3}^{-}$, so the name is calcium chlorate. Rubidium cyanate: Rubidium has a + 1 charge ($Rb^{+}$) and cyanate is $OCN^{-}$, so the formula is $RbOCN$. Copper(II) sulfate: Copper(II) has a + 2 charge ($Cu^{2 + }$) and sulfate is $SO_{4}^{2 - }$, so the formula is $CuSO_{4}$. Calcium hydroxide: Formula is $Ca(OH){2}$. Tin(II) oxide: Tin(II) has a + 2 charge ($Sn^{2 + }$) and oxide is $O^{2 - }$, so the formula is $SnO$. Aluminum bicarbonate: Aluminum has a + 3 charge ($Al^{3 + }$) and bicarbonate is $HCO{3}^{-}$, so the formula is $Al(HCO_{3}){3}$. Sodium perchlorate: Sodium has a + 1 charge ($Na^{+}$) and perchlorate is $ClO{4}^{-}$, so the formula is $NaClO_{4}$. Copper(I) dichromate: Copper(I) has a + 1 charge ($Cu^{+}$) and dichromate is $Cr_{2}O_{7}^{2 - }$, so the formula is $Cu_{2}Cr_{2}O_{7}$. $I_{4}O_{9}$: The name is tetraiodine nonoxide. $ZnS$: The name is zinc sulfide. Difluorine octachloride: The formula is $F_{2}Cl_{8}$. $NBr_{3}$: The name is nitrogen tribromide. $Fe(ClO)_{3}$: Iron(III) has a + 3 charge ($Fe^{3 + }$) and hypochlorite is $ClO^{-}$, so the name is iron(III) hypochlorite.

Answer:

74. Barium sulfate
75. $AgC_{2}H_{3}O_{2}$
76. Strontium sulfite
77. $Ni_{3}(PO_{4})_{2}$
78. Lithium bicarbonate
79. $(NH_{4}){3}PO{4}$
80. $Al_{2}(C_{2}O_{4})_{3}$
81. $Ca(OH)_{2}$
82. Ammonium hydroxide
83. $Rb_{2}Cr_{2}O_{7}$
84. Copper(I) chlorate
85. Titanium(IV) hydroxide
86. $NH_{4}Cl$
87. Calcium chlorate
88. $RbOCN$
89. $CuSO_{4}$
90. $Ca(OH)_{2}$
91. $SnO$
92. $Al(HCO_{3})_{3}$
93. $NaClO_{4}$
94. $Cu_{2}Cr_{2}O_{7}$
95. Tetraiodine nonoxide
96. Zinc sulfide
97. $F_{2}Cl_{8}$
98. Nitrogen tribromide
99. Iron(III) hypochlorite