one half of a balanced chemical equation is shown.\n3mg(oh)₂ + 2h₃po₄\nwhich lists the numbers of each atom…
one half of a balanced chemical equation is shown.\n3mg(oh)₂ + 2h₃po₄\nwhich lists the numbers of each atom the other half of the equation would contain?\n3 mg, 2 p, 14 o, 12 h\nmg, 2 p, 14 o, 6 h\n3 mg, 8 p, 7 o, 6 h\n6 mg, 6 p, 2 o, 12 h
Answer
Explanation:
Step1: Count Mg atoms
In $3Mg(OH)_2$, the coefficient of Mg is 3, so there are 3 Mg atoms.
Step2: Count P atoms
In $2H_3PO_4$, the coefficient of P is 2, so there are 2 P atoms.
Step3: Count O atoms
In $3Mg(OH)_2$, the number of O atoms is $3\times2 = 6$. In $2H_3PO_4$, the number of O atoms is $2\times4=8$. So in total, there are $6 + 8=14$ O atoms.
Step4: Count H atoms
In $3Mg(OH)_2$, the number of H atoms is $3\times2 = 6$. In $2H_3PO_4$, the number of H atoms is $2\times3 = 6$. So in total, there are $6+6 = 12$ H atoms.
Answer:
3 Mg, 2 P, 14 O, 12 H