one half of a balanced chemical equation is shown.\n3mg(oh)₂ + 2h₃po₄\nwhich lists the numbers of each atom…
one half of a balanced chemical equation is shown.\n3mg(oh)₂ + 2h₃po₄\nwhich lists the numbers of each atom the other half of the equation would contain?\no 3mg, 2p, 14o, 12h\no mg, 2p, 14o, 6h\no 3mg, 8p, 7o, 6h\no 6mg, 6p, 2o, 12h
Answer
Explanation:
Step1: Count Mg atoms
In $3Mg(OH)_2$, the coefficient of $Mg$ is 3, so there are 3 Mg atoms.
Step2: Count P atoms
In $2H_3PO_4$, the coefficient of P is 2, so there are 2 P atoms.
Step3: Count O atoms
In $3Mg(OH)_2$, the number of O atoms is $3\times2 = 6$. In $2H_3PO_4$, the number of O atoms is $2\times4=8$. So in total, $6 + 8=14$ O atoms.
Step4: Count H atoms
In $3Mg(OH)_2$, the number of H atoms is $3\times2 = 6$. In $2H_3PO_4$, the number of H atoms is $2\times3 = 6$. So in total, $6+6 = 12$ H atoms.
Answer:
3 Mg, 2 P, 14 O, 12 H