ordering 1 point consider three samples of a different gas present in containers that have a different…

Explanation:

Step1: Recall density formula

Density $\rho=\frac{m}{V}$, where $m$ is mass and $V$ is volume. We need to estimate mass and volume for each sample. Assume the volume of each container is $V_A$, $V_B$, $V_C$ and the mass of particles in each container is $m_A$, $m_B$, $m_C$.

Step2: Count particles and their masses for Sample A

In Sample A, assume there are $n_A = 8$ particles with mass $m$ each. So $m_A=8m$.

Step3: Count particles and their masses for Sample B

In Sample B, there are $n_B = 7$ particles with mass $2m$ each. So $m_B = 7\times2m=14m$.

Step4: Count particles and their masses for Sample C

In Sample C, there are $n_C=10$ particles with mass $3m$ each. So $m_C=10\times3m = 30m$.

Step5: Compare densities

Since we don't know the volumes precisely, but assume for simplicity that the volumes of the containers are such that we can compare the mass - to - volume ratios. If we assume the volumes are similar (since no information about volume difference is given other than they are different), we can compare the masses directly as a first - order approximation. The density of Sample A is $\rho_A=\frac{m_A}{V_A}$, Sample B is $\rho_B=\frac{m_B}{V_B}$, Sample C is $\rho_C=\frac{m_C}{V_C}$. Since $m_C>m_B>m_A$ (assuming volumes are comparable), the order of densities is $\rho_C>\rho_B>\rho_A$.

Answer:

The density of Sample C > the density of Sample B > the density of Sample A.