what is the original concentration of a solution in which 50.0 ml of the concentrated solution is diluted to…

Explanation:

Step1: Recall dilution formula

The dilution formula is $C_1V_1 = C_2V_2$, where $C_1$ is the initial concentration, $V_1$ is the initial volume, $C_2$ is the final concentration, and $V_2$ is the final volume.

Step2: Identify given values

We have $V_1 = 50.0\ mL$, $V_2=1000\ mL$, and $C_2 = 0.1\ M$.

Step3: Solve for $C_1$

Rearranging the formula for $C_1$ gives $C_1=\frac{C_2V_2}{V_1}$. Substituting the values: $C_1=\frac{0.1\ M\times1000\ mL}{50.0\ mL}$. $C_1 = 2\ M$

Answer:

$2$