what is the original concentration of a solution in which 83.5 ml of the concentrated solution is diluted to…
what is the original concentration of a solution in which 83.5 ml of the concentrated solution is diluted to 500. ml of 0.5 m solution? ? m solution
Answer
Explanation:
Step1: Recall dilution formula
$C_1V_1 = C_2V_2$
Step2: Identify given values
$V_1=83.5\ mL$, $V_2 = 500\ mL$, $C_2=0.5\ M$
Step3: Solve for $C_1$
$C_1=\frac{C_2V_2}{V_1}=\frac{0.5\ M\times500\ mL}{83.5\ mL}$ $C_1=\frac{250}{83.5}\ M\approx 3.0\ M$
Answer:
$3.0$