what are the oxidation numbers of the atoms in this reaction? check all that apply. ch₄(g) + 2o₂(g) → co₂(g)…

what are the oxidation numbers of the atoms in this reaction? check all that apply. ch₄(g) + 2o₂(g) → co₂(g) + 2h₂o(g) -4 for c in ch₄ +4 for c in co₂ -2 for o in all substances +1 for h in both ch₄ and h₂o +4 for o in h₂o done

what are the oxidation numbers of the atoms in this reaction? check all that apply. ch₄(g) + 2o₂(g) → co₂(g) + 2h₂o(g) -4 for c in ch₄ +4 for c in co₂ -2 for o in all substances +1 for h in both ch₄ and h₂o +4 for o in h₂o done

Answer

Explanation:

Step1: Determine C in CH₄

Hydrogen has an oxidation number of +1 in most compounds. In CH₄, let the oxidation number of C be (x). Since there are 4 H atoms, we have (x+(+1)\times4 = 0) (neutral compound), so (x=- 4).

Step2: Determine C in CO₂

Oxygen has an oxidation - number of - 2 in most compounds. In CO₂, let the oxidation number of C be (y). Since there are 2 O atoms, we have (y+(-2)\times2 = 0), so (y = + 4).

Step3: Determine O oxidation number

Oxygen has an oxidation number of - 2 in most compounds, but in O₂ its oxidation number is 0. In CO₂ and H₂O, O has an oxidation number of - 2.

Step4: Determine H oxidation number

Hydrogen has an oxidation number of +1 in most compounds. In CH₄ and H₂O, H has an oxidation number of +1.

Answer:

-4 for C in CH₄, +4 for C in CO₂, +1 for H in both CH₄ and H₂O